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प्रश्न
The 6th term from the end of the G.P. 8, 4, 2, ......., $$\frac{1}{1024}$$ is ______.
विकल्प
$$\frac{1}{32}$$
$$\frac{1}{16}$$
$$\frac{1}{64}$$
$$\frac{1}{128}$$
MCQ
रिक्त स्थान भरें
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उत्तर
The 6th term from the end of the G.P. 8, 4, 2, ......., $$\frac{1}{1024}$$ is `underlinebb(1/32)`.
Explanation:
The common ratio is $$\frac12$$. The sixth term from the end is $$\frac{1/1024}{(1/2)^5} = \frac{32}{1024} = \frac1{32}$$.
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