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Question
The 3rd and 6th terms of a G.P. are 40 and 320, then find the progression.
Sum
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Solution
T3 ⇒ ar2 = 40
T6 ⇒ ar5 = 320
`(ar^5)/(ar^2) = 320/40`
r3 = 8
r = 2
a(4) = 40
a = `40/4`
a = 10
GP ⇒ a, ar, ar2 ...
10, 20, 40, ....
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