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Question
The 3rd, 7th, and 11th terms of a G.P. are x, y, and z, respectively, then prove that y2 = xz.
Theorem
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Solution
`Tn = ar^(n-1)`
T3 = ar2
T7 = ar6
T11 = ar10
To prove: y2 = xz
LHS ⇒ `(ar^6)^2 = a^2r^12`
RHS ⇒ (ar2) (ar10) = a2r12
LHS = RHS hence proved.
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