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∫ Tan 2 ( 2 X − 3 ) D X

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Question

\[\int \tan^2 \left( 2x - 3 \right) dx\]

Sum
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Solution

\[\int \tan^2 \left( 2x - 3 \right)dx\]
\[ = \int\left[ \sec^2 \left( 2x - 3 \right) - 1 \right]dx\]
\[ = \int \sec^2 \left( 2x - 3 \right)dx - \int1dx\]
\[ = \frac{\text{tan } \left( 2x - 3 \right)}{2} - x + C\]

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Chapter 18: Indefinite Integrals - Exercise 19.03 [Page 23]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 18 Indefinite Integrals
Exercise 19.03 | Q 18 | Page 23
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