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∫ Tan 2 ( 2 X − 3 ) D X - Mathematics

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प्रश्न

\[\int \tan^2 \left( 2x - 3 \right) dx\]

योग
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उत्तर

\[\int \tan^2 \left( 2x - 3 \right)dx\]
\[ = \int\left[ \sec^2 \left( 2x - 3 \right) - 1 \right]dx\]
\[ = \int \sec^2 \left( 2x - 3 \right)dx - \int1dx\]
\[ = \frac{\text{tan } \left( 2x - 3 \right)}{2} - x + C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.03 [पृष्ठ २३]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.03 | Q 18 | पृष्ठ २३

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