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∫ Log ( X + 1 ) D X

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Question

\[\int\text{ log }\left( x + 1 \right) \text{ dx }\]
Sum
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Solution

\[\int \text{ log } \left( x + 1 \right)dx\]
\[ = \int1 . \log \left( x + 1 \right)dx\]
\[\text{Taking log} \left( x + 1 \right) \text{ as the first function and 1 as the second function} . \]
\[ = \text{ log }\left( x + 1 \right)\int \text{ 1 dx } - \int\left[ \frac{d}{dx}\left\{ \log\left( x + 1 \right) \right\}\int1 dx \right]dx\]
\[ = x \text{ log} \left( x + 1 \right) - \int\frac{x}{x + 1}dx\]
\[ = x \text{ log }\left( x + 1 \right) - \int\frac{x + 1}{x + 1} - \frac{1}{x + 1}dx\]
\[ = x \text{  log }\left( x + 1 \right) - x + \text{ log } \left| x + 1 \right| + C\]

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Chapter 18: Indefinite Integrals - Exercise 19.25 [Page 133]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 18 Indefinite Integrals
Exercise 19.25 | Q 2 | Page 133
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