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Question
Suresh has a recurring deposit account in a bank. He deposits ₹ 2000 per month and the bank pays interest at the rate of 8% per annum. If he gets ₹ 1040 as interest at the time of maturity, find in years total time for which the account was held.
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Solution
Deposit per month P = ₹ 2000
Rate of interest R = 8%
Interest earned, I = ₹ 1040
Let n months be the length of time for which money is invested.
Then, by formula
I = `(P xx n(n + 1))/(2 xx 12) xx r/100`
1040 = `2000 xx (n(n + 1))/(2 xx 12) xx 8/100`
1040 = `(20 xx n xx (n + 1))/3`
52 × 3 = n2 + n
n2 + n – 156 = 0
n2 + 13n – 12n – 156 = 0
n(n + 13) – 12(n + 13) = 0
(n – 12)(n + 13) = 0
n = 12 ...(∵ n = –13, is not possible)
As a result, the time period for which money is invested is 12 months or 1 year.
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| 05.01.2008 | By B/F | 24650.00 | ||
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Akash, an employee of a bank, has a saving bank account in his bank that pays him
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| Feb. 3, 1981 | By cash | - | 500·00 | 500·00 |
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