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Question
Shilpa has a 4 year recurring deposit account in Bank of Maharashtra and deposits Rs 800 per month. If she gets Rs 48200 at the time of maturity, find
- the rate of simple interest.
- the total interest earned by Shilpa.
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Solution
Deposit per month (P) = Rs 800
Amount of maturity = Rs 48200
Period (n) = 4 years = 48 months
Let rate of interest be R% p.a.
Total principal for one month
= `(P(n)(n + 1))/(2)`
= `(800 xx 48 xx (48 + 1))/(2)`
= `₹(800 xx 48 xx 49)/(2)`
= ₹ 940800
Total deposit:
= ₹ 800 × 48
= ₹ 38400
and amount of maturity
= ₹ 48200
∴ Interest earned
= ₹ 48200 − ₹ 38400
= ₹ 9800
(i) Rate of interest
= `("S.I" xx 100)/("P" xx "T")`
= `(9800 xx 100 xx 12)/(940800)`
= 12.5%
(ii) Total interest earned by Shilpa
= ₹ 9800
RELATED QUESTIONS
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| Feb 8 Feb 18 April 12 June 15 July 8 |
B/F To self By Cash To Self By Cash |
- Rs. 4,000 - Rs. 5,000 - |
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Rs. 8,500 4500 6730 1730 7730 |
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| Date | Particulars | Withdrawals (Rs) | Deposits (Rs) |
| 2.1.10 | By cash | 250.00 | |
| 9.1.10 | By Cheque | 825.00 | |
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Deposits (in ₹) |
Balance (in ₹) |
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Amount Deposits(₹) | Amount Balance(₹) |
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| Jan. 11, 2007 | By Cheque | - | 3,000·00 | 4,000·00 |
| Feb. 3, 2007 | By Cash | - | 2,500·00 | 6,500·00 |
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| May 25, 2007 | By Cash | - | 2,000·00 | 11,500·000 |
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| Aug 29, 2007 | To Cheque | 1,000·00 | - | 14,000·00 |
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