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Question
Suggest the route for the preparation of the following from benzene.
Bromo benzene
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Solution
Bezene undergo bromination to give bromobenzene.
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{...........................}|\\
\ce{CH3 - C = CH2 + HBr ->[Benzoyl][peroxide] H3C - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH3}\phantom{.................................}
\end{array}\]
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