Advertisements
Advertisements
Question
Subtract 3x − 4y − 7z from the sum of x − 3y + 2z and − 4x + 9y − 11z.
Advertisements
Solution
Let first add the expressions
\[x - 3y + 2z \text { and } - 4x + 9y - 11z\] We get:
\[\left( x - 3y + 2z \right) + \left( - 4x + 9y - 11z \right)\]
\[= x - 3y + 2z - 4x + 9y - 11z\]
\[= x - 4x - 3y + 9y + 2z - 11z\] (Collecting like terms)
\[= - 3x + 6y - 9z\] (Combining like terms)
Now, subtracting the expression
\[3x - 4y - 7z\] from the above sum; we get:
\[\left( - 3x + 6y - 9z \right) - \left( 3x - 4y - 7z \right)\]
\[ = - 3x + 6y - 9z - 3x + 4y + 7z\]
\[= - 3x - 3x + 6y + 4y - 9z + 7z\] (Collecting like terms)
\[= - 6x + 10y - 2z\] (Combining like terms)
Thus, the answer is \[- 6x + 10y - 2z\].
RELATED QUESTIONS
Add the following:
ab − bc, bc − ca, ca − ab
Add the following:
a − b + ab, b − c + bc, c − a + ac
Subtract: (a - b) from (a + b)
From the sum of 4 + 3x and 5 - 4x + 2x2, subtract the sum of 3x2 - 5x and -x2 + 2x + 5.
Add the following algebraic expression:
\[\frac{11}{2}xy + \frac{12}{5}y + \frac{13}{7}x, - \frac{11}{2}y - \frac{12}{5}x - \frac{13}{7}xy\]
Solve:
(6a − 5b − 8c) + (15b + 2a − 5c)
If x is a natural number, then x + 1 is its predecessor
Add the following expressions:
x3 – x2y – xy2 – y3 and x3 – 2x2y + 3xy2 + 4y
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
What should be added to 3pq + 5p2q2 + p3 to get p3 + 2p2q2 + 4pq?
