Advertisements
Advertisements
Question
Simplify: n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
Sum
Advertisements
Solution
n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
= n + m + 1 + n + 2 + m + 3 + n + 4 + m + 5
= n + n + n + m + m + m + 1 + 2 + 3 + 4 + 5
= (1 + 1 + 1)n + (1 + 1 + 1)m + 15
= 3n + 3m + 15
= 3m + 3n + 15
shaalaa.com
Is there an error in this question or solution?
Chapter 3: Algebra - Exercise 3.2 [Page 63]
APPEARS IN
RELATED QUESTIONS
Add the following:
l2 + m2, m2 + n2, n2 + l2, 2lm + 2mn + 2nl
Subtract: 4a − 7ab + 3b + 12 from 12a − 9ab + 5b − 3
Add: 3p2q2 - 4pq + 5, - 10p2q2, 15 + 9pq + 7p2q2
Add: ab - 4a, 4b - ab, 4a - 4b
What should be taken away from 3x2 - 4y2 + 5xy + 20 to obtain - x2 - y2 + 6xy + 20?
Subtract:
2a − b from 3a − 5b
Add:
9p + 16q; 13p + 2q
Add: 7mn, 5mn
Add the following expressions:
p2 – q + r, q2 – r + p and r2 – p + q
Add the following expressions:
uv – vw, vw – wu and wu – uv
