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Question
Study the given table and answer the following questions:
| Parents | F1 | F2 |
| A pea plant with red flowers was crossed with a pea plant with white flowers. | 30 seeds were sown and all bore plants with red flowers. | 44 seeds were sown, 33 plants bore red flowers and 11 plants bore white flowers. |
- Depict the information given in the table in the form of a cross.
- Deduce the F2 phenotypic ratio/F2 ratio showing external look aв well as genotypic/genetic makeup, ratio.
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Solution
a. To depict the cross, let us assume:
R = Dominant allele for red flowers
r = Recessive allele for white flowers
For parental generation (P):
Phenotype: Red flower × White flower
Genotype: RR × rr
Gametes: (R) and (r)
For the first filial generation (F1):
Genotype: Rr (Heterozygous Red)
Phenotype: All Red flowers (30 plants)
Selfing of F1 (Rr × Rr):
Gametes: (R), (r) and (R), (r)
For the second filial generation (F2):
| Gametes | R | r |
| R | RR | Rr |
| r | Rr | rr |
b. Based on the F2 data provided (33 red and 11 white plants) and the Punnett square above, we can deduce the following:
F2 phenotypic ratio (External look):
This ratio is based on the observable physical traits.
Red flowers : White flowers
33 : 11
The simplified Ratio is 3 : 1.
F2 genotypic ratio (Genetic makeup):
This ratio is based on the genetic combinations (RR, Rr, and rr).
Pure Red (RR) : Hybrid Red (Rr) : Pure White (rr)
According to Mendelian principles for a monohybrid cross:
The ratio is 1 : 2 : 1.
