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Question
Solve using quadratic formula:
3x2 + x − 4 = 0
Sum
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Solution
Given:
3x2 + x − 4 = 0
`x = (-b +- sqrt(b^2-4ac))/(2a)`
the coefficients are:
a = 3
b = 1
c = −4
`x = (-1+- sqrt((1)^2 - 4(3) (-4)))/(2(3))`
` = (-1 +- sqrt(1+48))/6`
`= (-1+- sqrt49)/6`
`= (-1 +-7)/6`
Case 1:
`x = (-1+7)/6 = 6/6 = 1`
Case 2:
`x = (-1-7)/6 = (-8)/6 = -4/3`
` x = 1 or x = -4/3`
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