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Question
Solve the pair of linear (simultaneous) equations by the method of elimination by substitution:
2x + 3y = 8,
2x = 2 + 3y
Sum
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Solution
Given:
2x + 3y = 8 ...(1)
2x = 2 + 3y ...(2)
From equation (2),
2x = 2 + 3y
Substitute this value of 2x in equation (1):
2 + 3y + 3y = 8
2 + 6y = 8
6y = 8 − 2
6y = 6
y = 1
Now substitute y = 1 in equation (2):
2x = 2 + 3(1)
2x = 5
`x = 5/2`
Hence,
`x = 5/2`, y = 1
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Methods of Solving Simultaneous Linear Equations by Elimination Method
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