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Solve the following problem. Two small and similar bar magnets have a magnetic dipole moment of 1.0 Am2 each. They are kept in a plane in such a way that their axes are perpendicular to each other.

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Question

Solve the following problem.

Two small and similar bar magnets have a magnetic dipole moment of 1.0 Am2 each. They are kept in a plane in such a way that their axes are perpendicular to each other. A line drawn through the axis of one magnet passes through the center of other magnet. If the distance between their centers is 2 m, find the magnitude of the magnetic field at the midpoint of the line joining their centers.

Sum
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Solution

Let P be the midpoint of the line joining the centres of two bar magnets. As shown in figure, P is at the axis of one bar magnet and at the equator of another bar magnet. Thus, the magnetic field on the axis of the first bar magnet at distance of 1 m from the centre will be,

Ba = `μ_0/(4π)(2"m")/"r"^3`

= `10^-7xx(2xx1.0)/(1)^3`

= 2 × 10−7 Wb/m2

Magnetic field on the equator of second bar magnet will be,

Beq = `μ_0/(4π)("m")/"r"^3`

= `10^-7xx1.0/(1)^3`

= 1 × 10−7 Wb/m2

The net magnetic field at P,

Bnet = `sqrt("B"_"a"^2+"B"_"eq"^2)`

= `sqrt((2xx10^-7)^2+(1xx10^-7)^2)`

= `sqrt((10^-7)^2xx(4+1))`

= `sqrt(5)xx10^-7` Wb/m2

Magnitude of net magnetic field at midpoint of line will be `sqrt(5)xx10^-7` Wb/m2.

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Chapter 12: Magnetism - Exercises [Page 228]

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Balbharati Physics [English] Standard 11 Maharashtra State Board
Chapter 12 Magnetism
Exercises | Q 4. (iii) | Page 228

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