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Solve the following Linear Programming Problem graphically: Maximize Z = 400x + 300y subject to x + y ≤ 200, x ≤ 40, x ≥ 20, y ≥ 0

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Question

Solve the following Linear Programming Problem graphically:

Maximize Z = 400x + 300y subject to x + y ≤ 200, x ≤ 40, x ≥ 20, y ≥ 0

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Solution

We have Z= 400x + 300y subject to x + y ≤ 200, x ≤ 40, x ≥ 20, y ≥ 0

The corner points of the feasible region are C(20, 0), D(40, 0), B(40, 160), A(20, 180)

Corner Point Z = 400x + 300y
C(20, 0) 8000
D(40, 0) 16000
B(40, 160) 64000
A(20, 180) 62000

Maximum profit occurs at x = 40, y = 160 and the maximum profit = ₹ 64,000

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