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Solve the following : Find the rate of interest compounded annually if an ordinary annuity of ₹20,000 per year amounts to ₹41,000 in 2 years.

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Question

Solve the following :

Find the rate of interest compounded annually if an ordinary annuity of ₹20,000 per year amounts to ₹41,000 in 2 years.

Sum
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Solution

Given, A = ₹41,000, C = ₹20,000, n = 2 years
We need to find r such that an ordinary annuity of ₹20,000 amounts to ₹41,000 in 2 years.

Since, A = `"C"/"i"[(1 + "i")^"n" - 1]`

41,000 = `"C"/"i"[(1 + "i")^2 - 1]`

41,000 = `(20,000)/"i"[(1 + "i")^2 - 1]`

`(41,000)/(20,000)= (1 + 2"i" + "i"^2 - 1)/"i"`

`(41)/(20) = ("i"^2 + 2"i")/"i"`

`(41)/(20)` = i + 2

`(41)/(20)` – 2 = i

`(41 - 40)/(20)` = i

∴ i = `(1)/(20)` = 0.05

But i = `"r"/(100)`

∴ 0.05 = `"r"/(100)`

∴ r = 5%
The rate of interest is 5%.

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Annuity
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Chapter 2: Insurance and Annuity - Miscellaneous Exercise 2 [Page 31]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 2 Insurance and Annuity
Miscellaneous Exercise 2 | Q 4.17 | Page 31

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Period, n = 20, r = 5%, (1.025)20 = 1.675

A = `"C"/"I" [(1 + "i")^"n" - 1]`

I = `5/200` = `square` as interest is calculated semi-annually

A = 10,00,000 = `"C"/"I" [(1 + "i")^"n" - 1]`

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= `"C"/0.025 [1.675 - 1]`

10,00,000 = `("C" xx 0.675)/0.025`

C = ₹ `square`


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