Question

Solve the following equation and check your result:

`(2x)/3 + 1 = (7x)/15 + 3`

Answer 1

`(2x)/3 + 1 = (7x)/15 + 3`

Transposing  `(7x)/15` to L.H.S and 1 to R.H.S, we obtain

`(2x)/3 - (7x)/15 = 3 - 1`

`(5 xx 2x - 7x)/15 = 2`

`(3x)/15 = 2`

`x/5 = 2`

Multiplying both sides by 5, we obtain

x = 10

L.H.S = `(2x)/3 + 1`

`= (2xx10)/3 + 1`

`= (2 xx 10 + 1 xx 3)/3 `

`= 23/3`

R.H.S = `(7x)/15 + 3`

`= (7 xx 10)/15 + 3`

`= (7 xx 2)/3 + 3`

`= 14/3 + 3`

`= (14 + 3 xx 3)/3`

`= 23/3`

L.H.S. = R.H.S.

Hence, the result obtained above is correct.