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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Solve the following differential equation: ddsin dydx = a, y(0) = 1

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Question

Solve the following differential equation:

`sin  ("d"y)/("d"x)` = a, y(0) = 1

Sum
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Solution

`sin  ("d"y)/("d"x)` = a

`sin  ("d"y)/("d"x)` = sin–1(a)

The equation can be written as

dy = sin–1(a) dx

Taking integration on both sides, we get

`int "d"y = int sin^-1 ("a")  "d"x`

y  = `sin^-1 "a" int "d"x`

y = sin–1(a) x + C  ........(1)

Initial condition:

Since y (0) = 1, we get

y = sin–1(a) x + C

1 = sin–1(a) (0) + C

0 + C = 1

C = 1

Equation (1)

⇒ y = sin–1(a) x + 1

y – 1 = sin–1(a) x

`(y - 1)/x` = sin–1(a)

`sin((y - 1)/x)` = a

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Solution of First Order and First Degree Differential Equations
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Chapter 10: Ordinary Differential Equations - Exercise 10.5 [Page 161]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 10 Ordinary Differential Equations
Exercise 10.5 | Q 4. (iii) | Page 161
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