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Question
Solve the following quadratic equations by factorization:
a2x2 - 3abx + 2b2 = 0
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Solution
a2x2 - 3abx + 2b2 = 0
⇒ a2x2 - 2abx - abx + 2b2 = 0
⇒ ax(ax - 2b) - b(ax - 2b) = 0
⇒ (ax - b)(ax - 2b) = 0
Therefore,
ax - b = 0
ax = b
x = b/a
or,
ax - 2b = 0
ax = 2b
x = 2b/a
Hence, x = b/a or x = 2b/a
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