English

Find two consecutive odd integers such that the sum of their squares is 394.

Advertisements
Advertisements

Question

Find two consecutive odd integers such that the sum of their squares is 394.

Sum
Advertisements

Solution

Let first odd integer = 2x + 1
Then second odd integer = 2x + 3
According to the condition,
(2x + 1)2 + (2x + 3)2 = 394
⇒ 4x2 + 4x + 1 + 4x2 + 12x + 9 = 394
⇒ 8x2 + 16x - 394 + 10 = 0
⇒ 8x2 + 16x - 384 = 0
⇒ x2 + 2x - 48 = 0     ...(Dividing by 8)
⇒ x2 + 8x - 6x - 48 = 0
⇒ x(x + 8) -6(x + 8) = 0
⇒ (x + 8)(x - 6) = 0
EIther x + 8 = 0,
then x = -8
or
x - 6 = 0,
then x = 6
(i) If x = -8, then first odd integer = 2x + 1
= 2 x (-8) + 1
= -16 + 1
= -15
(ii) If x = 6, then first odd integer = 2x + 1
= 2 x 6 + 1 = 13
and second integer = 13 + 2 = 15
∴ Required integers are -15, -13, or 13, 15.

shaalaa.com
  Is there an error in this question or solution?
Chapter 5: Quadratic Equations in One Variable - Exercise 5.5

APPEARS IN

ML Aggarwal Understanding Mathematics [English] Class 10 ICSE
Chapter 5 Quadratic Equations in One Variable
Exercise 5.5 | Q 2.4
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×