Question

Solve the following quadratic equation by factorisation.

 2y² + 27y + 13 = 0

Answer 1

 2y² + 27y + 13 = 0
\[2 y^2 + 26y + y + 13 = 0\]
\[ \Rightarrow 2y\left( y + 13 \right) + \left( y + 13 \right) = 0\]
\[ \Rightarrow \left( 2y + 1 \right)\left( y + 13 \right) = 0\]
\[ \Rightarrow \left( 2y + 1 \right) = 0 \text{ or }  \left( y + 13 \right) = 0\]
\[ \Rightarrow y = \frac{- 1}{2} \text{ or } y = - 13\] 

So,  \[\frac{- 1}{2} \text{ and } - 13\] are the roots of the given quadratic equation.