Advertisements
Advertisements
Question
Solve the following quadratic equation using formula method only
16x2 - 24x = 1
Advertisements
Solution
16x2 - 24x = 1
16x2 - 24x - 1 = 0
a = 16 ; b = -24 ; c = -1
D = b2 - 4ac
= (-24)2 - 4(16)(-1)
= 576 + 64
= 640
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(24 +- 8 sqrt 10)/32`
x = `(3 + sqrt 10)/4` , x = `(3 - sqrt 10)/4`
APPEARS IN
RELATED QUESTIONS
Find the values of k for which the quadratic equation 9x2 - 3kx + k = 0 has equal roots.
If x=−`1/2`, is a solution of the quadratic equation 3x2+2kx−3=0, find the value of k
Find the nature of the roots of the following quadratic equation. If the real roots exist, find them:
2x2 - 3x + 5 = 0
Find the values of k for which the given quadratic equation has real and distinct roots:
kx2 + 6x + 1 = 0
If 1 is a root of the quadratic equation 3x2 + ax – 2 = 0 and the quadratic equation a(x2 + 6x) – b = 0 has equal roots, find the value of b ?
Determine the nature of the roots of the following quadratic equation :
x2 -5x+ 7= 0
In each of the following, determine whether the given numbers are roots of the given equations or not; 3x2 – 13x – 10 = 0; 5, `(-2)/(3)`
Find the values of k so that the quadratic equation (4 – k) x2 + 2 (k + 2) x + (8k + 1) = 0 has equal roots.
If (x – a) is one of the factors of the polynomial ax2 + bx + c, then one of the roots of ax2 + bx + c = 0 is:
State whether the following quadratic equation have two distinct real roots. Justify your answer.
(x + 1)(x – 2) + x = 0
