Advertisements
Advertisements
Question
Solve equation using factorisation method:
x2 – (a + b)x + ab = 0
Advertisements
Solution
x2 – (a + b)x + ab = 0
⇒ x2 – ax – bx + ab = 0
⇒ x(x – a) – b(x – a) = 0
⇒ (x – a)(x – b) = 0
Since x – a = 0 or x – b = 0
Then x = a or x = b
RELATED QUESTIONS
Solve the following quadratic equations by factorization:
`10x-1/x=3`
Solve the following quadratic equations by factorization:
`4sqrt3x^2+5x-2sqrt3=0`
The number of quadratic equations having real roots and which do not change by squaring their roots is
Solve the following equation: 3x2 + 25 x + 42 = 0
Solve the following equation: `("a+b")^2 "x"^2 - 4 "abx" - ("a - b")^2 = 0`
In each of the following, determine whether the given values are solution of the given equation or not:
`x^2 - sqrt(2) - 4 = 0; x = -sqrt(2), x = -2sqrt(2)`
Solve the following equation by factorization
21x2 – 8x – 4 = 0
Solve the following equation by factorization
`(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2(1)/(2)`
Divide 16 into two parts such that the twice the square of the larger part exceeds the square of the smaller part by 164.
The product of two successive integral multiples of 5 is 300. Then the numbers are:
