Advertisements
Advertisements
प्रश्न
Solve equation using factorisation method:
x2 – (a + b)x + ab = 0
Advertisements
उत्तर
x2 – (a + b)x + ab = 0
⇒ x2 – ax – bx + ab = 0
⇒ x(x – a) – b(x – a) = 0
⇒ (x – a)(x – b) = 0
Since x – a = 0 or x – b = 0
Then x = a or x = b
संबंधित प्रश्न
Solve the following quadratic equation for x: x2 – 2ax – (4b2 – a2) = 0
Solve for x: `(x-3)/(x-4)+(x-5)/(x-6)=10/3; x!=4,6`
The numerator of a fraction is 3 less than its denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and original fraction is `29/20`. Find the original fraction.
Solve the following quadratic equations by factorization:
`7x + 3/x=35 3/5`
Solve the following quadratic equation by factorisation.
`sqrt2 x^2 + 7x + 5sqrt2 = 0` to solve this quadratic equation by factorisation, complete the following activity.
`sqrt2 x^2 + 7x + 5sqrt2 = 0`
`sqrt2x^2+square+square+5sqrt2=0`
`x("______") + sqrt2 ("______") = 0`
`("______") (x + sqrt2) = 0`
`("______") = 0 or (x + sqrt2) = 0`
∴ x = `square or x = -sqrt2`
∴ `square` and `-sqrt(2)` are roots of the equation.
Solve the following quadratic equation by factorization: \[\frac{a}{x - b} + \frac{b}{x - a} = 2\]
Find the value of k for which the following equations have real and equal roots:
\[\left( k + 1 \right) x^2 - 2\left( k - 1 \right)x + 1 = 0\]
Solve the following equation: a2b2x2 + b2x - a2x - 1 = 0
Solve the following quadratic equation by factorisation:
2x2 + ax - a2 = 0 where a ∈ R.
If the sum of two smaller sides of a right – angled triangle is 17cm and the perimeter is 30cm, then find the area of the triangle.
