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Question
Solve: `y(1 - x) - x ("d"y)/("d"x)` = 0
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Solution
`y(1 - x) - x ("d"y)/("d"x)` = 0
`y(1 - x) = x ("d"y)/("d"x)`
⇒ `((1 - x))/x "d"x = 1/y "d"y`
`(1/x - x/x) "d"x = 1/y "d"y`
⇒ `(1/x - 1) "d"x = 1/y "d"y`
Integrating on both sides
`int (1/x - 1) "d"x = int 1/y "d"y`
`log x - x = log y + "c"`
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