Advertisements
Advertisements
Question
Solve : 3(2x + 1) - 2x+2 + 5 = 0.
Advertisements
Solution
3(2x + 1) - 2x+2 + 5 = 0.
⇒ 3 x 2x + 3 - 2x x 22 + 5 = 0
⇒ 2x ( 3 - 22 ) + 8 = 0
⇒ 2x ( 3 - 4 ) = - 8
⇒ 2x x ( - 1 ) = - 8
⇒ 2x = 8
⇒ 2x = 23
⇒ x = 3
APPEARS IN
RELATED QUESTIONS
Evaluate : `(64)^(2/3) - root(3)(125) - 1/2^(-5) + (27)^(-2/3) xx (25/9)^(-1/2)`
If 34x = ( 81 )-1 and `10^(1/y) = 0.0001, "Find the value of " 2^(- x ) xx 16^y `
Evaluate :
`[ 2^n xx 6^(m + 1 ) xx 10^( m - n ) xx 15^(m + n - 2)]/[4^m xx 3^(2m + n) xx 25^(m - 1)]`
Prove that: `a^-1/(a^-1+b^-1) + a^-1/(a^-1 - b^-1) = (2b^2)/(b^2 - a^2 )`
Simplify : `3"x"-[3"x"-{3"x"-(3"x"-overline(3"x"-"y"))}]`
Simplify : `2[6 + 4 {"m"-6(7 - overline("n"+"p")) + "q"}]`
Simplify: x5 ÷ (x2 × y2) × y3
Simplify the following:
`("a"^(1/3) + "a"^(-1/3))("a"^(2/3) - 1 + "a"^(-2/3))`
Simplify the following:
`(3^(x + 1) + 3^x)/(3^(x + 3) - 3^(x + 1)`
Simplify the following:
`(2^"m" xx 3 - 2^"m")/(2^("m" + 4) - 2^("m" + 1)`
