Advertisements
Advertisements
प्रश्न
Solve : 3(2x + 1) - 2x+2 + 5 = 0.
Advertisements
उत्तर
3(2x + 1) - 2x+2 + 5 = 0.
⇒ 3 x 2x + 3 - 2x x 22 + 5 = 0
⇒ 2x ( 3 - 22 ) + 8 = 0
⇒ 2x ( 3 - 4 ) = - 8
⇒ 2x x ( - 1 ) = - 8
⇒ 2x = 8
⇒ 2x = 23
⇒ x = 3
APPEARS IN
संबंधित प्रश्न
Evaluate : `((x^q)/(x^r))^(1/(qr)) xx ((x^r)/(x^p))^(1/(rp)) xx ((x^p)/(x^q))^(1/(pq))`
Simplify : −3 (1 − x2) − 2{x2 − (3 − 2x2)}
Simplify : `3"x"-[4"x"-overline(3"x"-5"y")-3 {2"x"-(3"x"-overline(2"x"-3"y"))}]`
Write each of the following in the simplest form:
`"a"^(1/3) ÷ "a"^(-2/3)`
Write each of the following in the simplest form:
a-3 x a2 x a0
Simplify the following and express with positive index:
3p-2q3 ÷ 2p3q-2
Simplify the following and express with positive index:
`[("p"^-3)^(2/3)]^(1/2)`
Simplify the following:
`(8 xx^6y^3)^(2/3)`
Simplify the following:
`(5^x xx 7 - 5^x)/(5^(x + 2) - 5^(x + 1)`
Simplify the following:
`(5^("n" + 2) - 6.5^("n" + 1))/(13.5^"n" - 2.5^("n" + 1)`
