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Question
Simplify the following and express with a positive index:
`(32)^(-2/5) ÷ (125)^(-2/3)`
Sum
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Solution
`(32)^(-2/5) ÷ (125)^(-2/3)`
= `[(32)^(-2/5)/(125)^(-2/3)]`
= `(125)^(2/3)/(32)^(2/5)`
= `( 5 xx 5 xx 5 )^(2/3)/( 2 xx 2 xx 2 xx 2 xx 2 )^(2/5)`
= `(5^3)^(2/3)/(2^5)^(2/5)`
= `5^2/2^2`
= `25/4`
= `(5/2)^2`
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Laws of Exponents
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