Advertisements
Advertisements
Question
Simplify (ab + bc)2 − 2ab2c
Advertisements
Solution
(ab + bc)2 − 2ab2c
= (ab)2 + 2(ab)(bc) + (bc)2 − 2ab2c [(a + b)2 = a2 + 2ab + b2 ]
= a2b2 + 2ab2c + b2c2 − 2ab2c
= a2b2 + b2c2
RELATED QUESTIONS
Use a suitable identity to get the following products.
(6x − 7) (6x + 7)
Use a suitable identity to get the following products.
(− a + c) (− a + c)
Use a suitable identity to get the following products.
(7a − 9b) (7a − 9b)
Find the following squares by suing the identities.
(6x2 − 5y)2
Use a formula to multiply of (2a – 13)(2a + 13)
Factorise the following using suitable identity
36m2 + 60m + 25
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
4x2 + 4x + 1
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
a2x2 + 2abx + b2
Factorise the following.
18 + 11x + x2
What should be added to 4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)?
