Advertisements
Advertisements
प्रश्न
Simplify (ab + bc)2 − 2ab2c
Advertisements
उत्तर
(ab + bc)2 − 2ab2c
= (ab)2 + 2(ab)(bc) + (bc)2 − 2ab2c [(a + b)2 = a2 + 2ab + b2 ]
= a2b2 + 2ab2c + b2c2 − 2ab2c
= a2b2 + b2c2
संबंधित प्रश्न
Use a suitable identity to get the following products.
(x + 3) (x + 3)
Use a suitable identity to get the following products.
(1.1m − 0.4) (1.1 m + 0.4)
Find the following squares by suing the identities.
(6x2 − 5y)2
Which of the options given below is the square of the binomial `(8-1/"x")`?
Expand:
`("y" - 3/"y")^2`
Use a formula to multiply of (2t – 5)(2t + 5)
Simplify: (a + b)2 – 4ab
Factorise the following, using the identity a2 + 2ab + b2 = (a + b)2.
`9x^2 + 2xy + y^2/9`
Verify the following:
(5x + 8)2 – 160x = (5x – 8)2
What should be added to 4c(– a + b + c) to obtain 3a(a + b + c) – 2b(a – b + c)?
