Advertisements
Advertisements
Question
Simplify: `(9^2 xx 7^3 xx 2^5)/(84^3)`
Sum
Advertisements
Solution
`(9^2 xx 7^3 xx 2^5)/(84^3) = ((3^2)^2 xx 7^3 xx 2^5)/(2^2 xx 3 xx 7)^3`
= `(3^(2 xx 2) xx 7^3 xx 2^5)/(2^(2 xx 3) xx 3^3 xx 7^3)`
= `(3^4 xx 7^3 xx 2^5)/(2^6 xx 3^3 xx 7^3)`
= 34−3 × 73−3 × 25−6
= 31 × 70 × 2−1
= 3 × 1 × 2−1
= `3 xx 1/2`
= `3/2`
shaalaa.com
Is there an error in this question or solution?
Chapter 1: Numbers - Exercise 1.6 [Page 45]
APPEARS IN
RELATED QUESTIONS
`(-1)^("even integer")` is _____________
(−2)−7 = ____________
`(-1/3)^(-5)` = ____________
Evaluate: (2−1 + 3−1) ÷ 6−1
Evaluate: (3−1 + 4−2 + 5−3)0
Which is not correct?
Find the value of:
70
Find the value of:
`(–7)^(2 xx 7 - 6 - 8)`
Find the value of:
(20 + 30 + 40) (40 – 30 – 20)
Find the value of:
2 × 3 × 4 ÷ 20 × 30 × 40
