Advertisements
Advertisements
प्रश्न
Simplify: `(9^2 xx 7^3 xx 2^5)/(84^3)`
योग
Advertisements
उत्तर
`(9^2 xx 7^3 xx 2^5)/(84^3) = ((3^2)^2 xx 7^3 xx 2^5)/(2^2 xx 3 xx 7)^3`
= `(3^(2 xx 2) xx 7^3 xx 2^5)/(2^(2 xx 3) xx 3^3 xx 7^3)`
= `(3^4 xx 7^3 xx 2^5)/(2^6 xx 3^3 xx 7^3)`
= 34−3 × 73−3 × 25−6
= 31 × 70 × 2−1
= 3 × 1 × 2−1
= `3 xx 1/2`
= `3/2`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 1: Numbers - Exercise 1.6 [पृष्ठ ४५]
APPEARS IN
संबंधित प्रश्न
For a ≠ 0, a0 is ______________
Evaluate: (50 + 6−1) × 33
Simplify: (32)3 × (2 × 35)−2 × (18)2
(−2)−3 × (−2)−2 = ____________
Which is not correct?
If `(10^x)/(10^(-3))` = 109, then x is ____________
By how much does `1/((10/11))` exceed `((1/10))/11`?
Order the following from the least to the greatest: 1625, 8100, 3500, 4400, 2600
(10 + 20 + 30) is equal to ______.
Which of the following is equal to 1?
