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Question
Simplify:\[\frac{32 m^2 n^3 p^2}{4mnp}\]
Sum
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Solution
\[\frac{32 m^2 n^3 p^2}{4mnp}\]
\[ = \frac{32 \times m \times m \times n \times n \times n \times p \times p}{4 \times m \times n \times p}\]
\[ = 8 m^{(2 - 1)} n^{(3 - 1)} p^{(2 - 1)} \]
\[ = 8m n^2 p\]
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