Advertisements
Advertisements
Question
Find whether the first polynomial is a factor of the second.
y − 2, 3y3 + 5y2 + 5y + 2
Advertisements
Solution
\[\frac{{3y}^3 {+5y}^2 +5y+2}{y-2}\]
\[ = \frac{{3y}^2 (y-2)+11y(y-2)+27(y-2)+56}{y-2}\]
\[ = \frac{{(y-2)(3y}^2 +11y+27)+56}{y-2}\]
\[ {=(3y}^2 +11y+27)+ \frac{56}{y-2}\]
\[ \because \text{Remainder} = 56\]
\[ \therefore \text{(y-2) is not a factor of}\ {3y}^3 {+5y}^2 +5y+2.\]
APPEARS IN
RELATED QUESTIONS
Divide the given polynomial by the given monomial.
(p3q6 − p6q3) ÷ p3q3
Which of the following expressions are not polynomials?
x2 + 2x−2
Which of the following expressions are not polynomials?
Divide 9x2y − 6xy + 12xy2 by −\[\frac{3}{2}\]
Divide x4 − 2x3 + 2x2 + x + 4 by x2 + x + 1.
Divide:
Divide: 8x − 10y + 6c by 2
Divide 24(x2yz + xy2z + xyz2) by 8xyz using both the methods.
7ab3 ÷ 14ab = 2b2
The denominator of a fraction exceeds Its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, we get `3/2`. Find the original fraction.
