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Show that the Vectors 2 ^ I − 3 ^ J + 4 ^ K and − 4 ^ I + 6 ^ J − 8 ^ K Are Collinear.

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Question

Show that the vectors \[2 \hat{i} - 3 \hat{j} + 4 \hat{k}\text{ and }- 4 \hat{i} + 6 \hat{j} - 8 \hat{k}\] are collinear.

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Solution

Given the position vectors \[2 \hat{i} - 3 \hat{j} + 4 \hat{k}\] and \[- 4 \hat{i} + 6 \hat{j} - 8 \hat{k}\]
Let \[\vec{a} = 2 \hat{i} - 3 \hat{j} + 4 \hat{k}\] and \[\vec{b} = - 4 \hat{i} + 6 \hat{j} - 8 \hat{k}\]
Then,
\[\vec{b} = - 4 \hat{i} + 6 \hat{j} - 8 \hat{k} \]
\[ = - 2\left( 2 \hat{i} - 3 \hat{j} + 4 \hat{k} \right)\]
\[ = - 2 \vec{a} \]
Hence, \[\vec{a} , \vec{b}\] are collinear.

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Chapter 22: Algebra of Vectors - Exercise 23.7 [Page 61]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 22 Algebra of Vectors
Exercise 23.7 | Q 7 | Page 61

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