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Show that the Function G (X) = X − [X] is Discontinuous at All Integral Points. Here [X] Denotes the Greatest Integer Function.

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Question

Show that the function g (x) = x − [x] is discontinuous at all integral points. Here [x] denotes the greatest integer function.

Sum
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Solution

Given: `g(x)=x-[x]`

It is evident that g is defined at all integral points.

Let \[n \in Z\] .

Then, 

`g(n)=n-[n]=n-n=0`

The left hand limit of at x = n is,

`lim_(x->n^-)g(x)=lim_(x->n^_)(x-[x])=lim_(x->n^_)(x) -lim_(x->n^_)[x]=n-(n-1)=1`

The right hand limit of f at n is, 

`lim_(x->n^+)g(x)=lim_(x->n^+)(x-[x])=lim_(x->n^+)(x)-lim_(x->n^+)[x]=n-n=0`

It is observed that the left and right hand limits of f at x = n do not coincide.

i.e.

\[\lim_{x \to n^-} g\left( x \right) \neq \lim_{x \to n^+} g\left( x \right)\]

So, f is not continuous at x = n,

\[n \in Z\]

Hence, g is discontinuous at all integral points.

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Chapter 8: Continuity - Exercise 9.2 [Page 37]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 8 Continuity
Exercise 9.2 | Q 12 | Page 37

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