English

The function f(x) = x |x| is ______.

Advertisements
Advertisements

Question

The function f(x) = x |x| is ______.

Options

  • continuous and differentiable at x = 0

  • continuous but not differentiable at x = 0

  • differentiable but not continuous at x = 0

  • neither differentiable nor continuous at x = 0

MCQ
Fill in the Blanks
Advertisements

Solution

The function f(x) = x |x| is continuous and differentiable at x = 0.

Explanation:

Given, the function is f(x) = x |x| for x ∈ R.

The function can be written as,

f(x) = `{{:(      x^2; x > 0),(-x^2; x ≤ 0):}`

Now, Rf(0) = `lim_(x rightarrow 0^+) (x^2)` = 0

and Lf(0) = `lim_(x rightarrow 0^-) (-x^2)` = 0

So, Lf(0) = Rf(0) = f(0)

So, the function is continuous at 0.

Now, Rf'(0) = `lim_(x rightarrow 0^+) (f(x) - f(0))/(x - 0)`

= `lim_(x rightarrow 0^+) (x^2 - 0)/x` = 0

and Lf'(0) = `lim_(x rightarrow 0^-) (f(x) - f(0))/(x - 0)`

= `lim_(x rightarrow 0^-) (-x^2 - 0)/x` = 0

So, Lf'(0) = Rf'(0)

So, function is differentiable at 0.

shaalaa.com
  Is there an error in this question or solution?
2022-2023 (March) Outside Delhi Set 1

RELATED QUESTIONS

Find the relationship between a and b so that the function f defined by f(x) = `{(ax + 1", if"  x<= 3),(bx + 3", if"  x > 3):}` is continuous at x = 3.


For what value of λ is the function defined by f(x) = `{(λ(x^2 - 2x)", if"  x <= 0),(4x+ 1", if"  x > 0):}` continuous at x = 0? What about continuity at x = 1?


Discuss the continuity of the following function:

f(x) = sin x × cos x


Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{(kx^2", if"  x<= 2),(3", if"  x > 2):}` at x = 2


Find the value of k so that the function f is continuous at the indicated point.

f(x) = `{(kx +1", if"  x<= pi),(cos x", if"  x > pi):}` at x = π


Determine the value of the constant k so that the function

\[f\left( x \right) = \begin{cases}\frac{\sin 2x}{5x}, if & x \neq 0 \\ k , if & x = 0\end{cases}\text{is continuous at x} = 0 .\]

 


Find the values of a so that the function 

\[f\left( x \right) = \begin{cases}ax + 5, if & x \leq 2 \\ x - 1 , if & x > 2\end{cases}\text{is continuous at x} = 2 .\]

If  \[f\left( x \right) = \frac{2x + 3\ \text{ sin }x}{3x + 2\ \text{ sin }  x}, x \neq 0\] If f(x) is continuous at x = 0, then find f (0).


In each of the following, find the value of the constant k so that the given function is continuous at the indicated point; \[f\left( x \right) = \begin{cases}(x - 1)\tan\frac{\pi  x}{2}, \text{ if } & x \neq 1 \\ k , if & x = 1\end{cases}\] at x = 1at x = 1


Discuss the continuity of the function  

\[f\left( x \right) = \left\{ \begin{array}{l}\frac{x}{\left| x \right|}, & x \neq 0 \\ 0 , & x = 0\end{array} . \right.\]

Find the points of discontinuity, if any, of the following functions: \[f\left( x \right) = \begin{cases}\frac{x^4 - 16}{x - 2}, & \text{ if } x \neq 2 \\ 16 , & \text{ if }  x = 2\end{cases}\]


Find the points of discontinuity, if any, of the following functions:  \[f\left( x \right) = \begin{cases}\frac{\sin x}{x} + \cos x, & \text{ if } x \neq 0 \\ 5 , & \text { if }  x = 0\end{cases}\]


Discuss the continuity of f(x) = sin | x |.


Determine the value of the constant 'k' so that function f 

\[\left( x \right) = \begin{cases}\frac{kx}{\left| x \right|}, &\text{ if }  x < 0 \\ 3 , & \text{ if } x \geq 0\end{cases}\]  is continuous at x  = 0  . 

 then f (x) is continuous for all
\[f\left( x \right) = \begin{cases}\frac{\left| x^2 - x \right|}{x^2 - x}, & x \neq 0, 1 \\ 1 , & x = 0 \\ - 1 , & x = 1\end{cases}\]  then f (x) is continuous for all

If \[f\left( x \right) = \begin{cases}\frac{1 - \sin x}{\left( \pi - 2x \right)^2} . \frac{\log \sin x}{\log\left( 1 + \pi^2 - 4\pi x + 4 x^2 \right)}, & x \neq \frac{\pi}{2} \\ k , & x = \frac{\pi}{2}\end{cases}\]is continuous at x = π/2, then k =

 


The value of f (0), so that the function

\[f\left( x \right) = \frac{\left( 27 - 2x \right)^{1/3} - 3}{9 - 3 \left( 243 + 5x \right)^{1/5}}\left( x \neq 0 \right)\] is continuous, is given by 


Let  \[f\left( x \right) = \frac{\tan\left( \frac{\pi}{4} - x \right)}{\cot 2x}, x \neq \frac{\pi}{4} .\]  The value which should be assigned to f (x) at  \[x = \frac{\pi}{4},\]so that it is continuous everywhere is


If  \[f\left( x \right) = x \sin\frac{1}{x}, x \neq 0,\]then the value of the function at x = 0, so that the function is continuous at x = 0, is

 


Find the values of a and b so that the function

\[f\left( x \right)\begin{cases}x^2 + 3x + a, & \text { if } x \leq 1 \\ bx + 2 , &\text {  if } x > 1\end{cases}\] is differentiable at each x ∈ R.

If f is defined by  \[f\left( x \right) = x^2 - 4x + 7\] , show that \[f'\left( 5 \right) = 2f'\left( \frac{7}{2} \right)\] 


Let f (x) = a + b |x| + c |x|4, where a, b, and c are real constants. Then, f (x) is differentiable at x = 0, if


If f.g is continuous at x = a, then f and g are separately continuous at x = a.


`lim_("x" -> 0) (1 - "cos" 4 "x")/"x"^2` is equal to ____________.


If `f(x) = {{:(-x^2",", "when"  x ≤ 0),(5x - 4",", "when"  0 < x ≤ 1),(4x^2 - 3x",", "when"  1 < x < 2),(3x + 4",", "when"  x ≥ 2):}`, then


What is the values of' 'k' so that the function 'f' is continuous at the indicated point


Which concept is fundamental in determining continuity of a function at a point?


If \[g\] is continuous and \[g(x)\neq 0\], which function is continuous?


Which conditions guarantee that \[f\circ g\] is continuous at \[c\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×