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Show that for the free fall of a body, the sum of the mechanical energy at any point in its path is constant.

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Question

Show that for the free fall of a body, the sum of the mechanical energy at any point in its path is constant.

Numerical
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Solution

Statement: The Law of Conservation of Mechanical Energy states that the total mechanical energy (sum of Potential Energy and Kinetic Energy) of a freely falling body remains constant at all points of its motion, provided no resistive forces (like air friction) are present.

Let a body of mass m be initially at rest at point A, which is at a vertical height h from the ground. As it falls freely under gravity, it passes through an intermediate point B after traveling a distance x, and finally touches the ground at point C.

1. Total Energy at Position A (At the Top-most Point):

Vertical height from the ground = h

Since the object is at rest, its initial velocity is u = 0

Potential Energy (PEA) = mgh

Kinetic Energy (KEA) = `1/2 "mu"^2`

= `1/2 m(0)^2`

= 0

Total Mechanical Energy (EA) = PEA + KEA

= mgh + 0

= mgh   ......(1)

2. Total Energy at Position B (At an Intermediate Point):

The body falls a downward distance x, so its remaining height above the ground becomes (h − x).

Let its velocity at point B be v1.

Using the equation of motion:

`v_1^2` = 0 + 2gx = 2gx

Kinetic Energy (KEB) = `1/2 mv_1^2`

= `1/2 m(2gx)`

= mgx

Potential Energy (PEB) = mg(h − x)

= mgh − mgx

Total Mechanical Energy (EB) = PEB + KEB

= (mgh − mgx) + mgx

= mgh   .......(2)

3. Total Energy at Position C (Just before hitting the Ground)

Total displacement traveled = h, and its final height from the ground becomes 0.

Let its final velocity at point C be v2.

Using the equation of motion:

v2 + u2 + 2as (where total displacement s = h)

`v_2^2` = 0 + 2gh = 2gh

Kinetic Energy (KEC) = `1/2 mv_2^2`

= `1/2 m(2gh)`

= mgh

Potential Energy (PEC): Since height is zero,

PEC = mg(0) = 0

Total Mechanical Energy (EC) = PEC + KEC

= 0 + mgh

= mgh  .....(3)

From Equations (1), (2), and (3), we observe that:

EA = EB = EC = mgh = Constant

As the body falls, its Potential Energy decreases while its Kinetic Energy increases by an equal amount. The sum of both mechanical energies remains completely constant throughout its path. This verifies the Law of Conservation of Mechanical Energy.

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Chapter 2: Work, Power and Energy - EXERCISE [Page 49]

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Lakhmir Singh Physics [English] Class 10 ICSE
Chapter 2 Work, Power and Energy
EXERCISE | Q 3. | Page 49
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