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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Show that cos π15 cos 2π15 cos 3π15 cos 4π15 cos 5π15 cos 6π15 cos 7π15=1128 - Mathematics

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Question

Show that `cos  pi/15  cos  (2pi)/15  cos  (3pi)/15  cos  (4pi)/15  cos  (5pi)/15  cos  (6pi)/15  cos  (7pi)/15 = 1/128`

Sum
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Solution

`(pi/15 = 12^circ)`

L.H.S = cos 12° cos 24° cos 36° cos 48° cos 60° cos 72° cos 84°  .....(1)

Consider (we know that)

cos A cos(60° + A) cos(60° – A)

= `cos "A" [cos^2 60^circ - sin^2"A"]`

= `cos "A"[1/4 - (1 - cos^2"A")]`

cos A cos(60° + A) cos(60° – A) = `1/4  cos 3"A"`

= `cos "A"[cos^2"A" - 3/4]`

= `(4cos^3 "A" - 3 cos "A")/4`

cos 12° cos 72° cos 48° = `1/4 cos 3(12^circ)`

= `1/4 cos 36^circ`

= `1/4[(sqrt(5) + 1)/4]`

Similarly cos 24° cos 84° cos 36° = `1/4 cos3 (12^circ)`

= `1/4 cos 72^circ`

= `1/4 cos(90^circ - 18^circ)`

= `1/4 sin 18^circ`

= `1/4[(sqrt(5) - 1)/4]`

(1) ⇒ L.H.S = `1/4[(sqrt(5) + 1)/4] * 1/4[(sqrt(5) - 1)/4] * 1/2`

= `1/4((sqrt(5) + 1)/4 * (sqrt(5) - 1)/4) * 1/2`

= `(5 - 1)/(128 xx 4)`

= `1/128`

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Trigonometric Functions and Their Properties
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Chapter 3: Trigonometry - Exercise 3.6 [Page 121]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 3 Trigonometry
Exercise 3.6 | Q 4 | Page 121

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