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Maharashtra State BoardSSC (English Medium) 10th Standard

Seg Nq is the Bisector of ∠ Nof δ Mnp. If Mn= 5, Pn =7,Mq = 2.5 Then Find Qp.

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Question

Seg NQ is the bisector of ∠ N
of Δ MNP. If MN= 5, PN =7,
MQ = 2.5 then find QP.

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Solution

MN = 5, PN = 7, MQ = 2.5, QP = ?
From the figure `(MN)/(NP)=(MQ)/(QP)`= ..............(Angle bisector theorem)
∴ `5/2.5 = 7/(QP)`

∴ 5 × QP = 7 × 2.5

∴ QP = `(7×2.5)/5`.

∴ QP = 3.5

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Property of an Angle Bisector of a Triangle
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2018-2019 (March) Balbharati Model Question Paper Set 2

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