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∫ Sec 2 X Tan X + 2 D X - Mathematics

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Question

\[\int\frac{\sec^2 x}{\tan x + 2} dx\]
Sum
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Solution

\[\text{Let I} = \int\frac{\sec^2 x}{\ tanx + 2}dx\]
\[\text{Putting}\ \tan x = t\]
\[ \Rightarrow \sec^2 x = \frac{dt}{dx}\]
\[ \Rightarrow \sec^2 x dx = dt\]
\[ \therefore I = \int\frac{1}{t + 2}dt\]
\[ = \text{ln} \left| t + 2 \right| + C\]
\[ = \text{ln} \left| \ tan\ x + 2 \right| + C \left[ \because t = \tan x \right]\]

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Chapter 19: Indefinite Integrals - Exercise 19.08 [Page 48]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.08 | Q 41 | Page 48

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