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∫ 1 1 − Cos 2 X D X - Mathematics

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Question

\[\int\frac{1}{1 - \cos 2x} dx\]
Sum
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Solution

\[\int\frac{dx}{1 - \cos \left( 2x \right)} \left[ \therefore 1 - \cos A = 2 \sin^2 \left( \frac{A}{2} \right) \right]\]
\[ = \int\frac{dx}{2 \sin^2 x}\]
\[ = \frac{1}{2}\int {cosec}^2 x dx\]
\[ = \frac{1}{2}\left[ - \cot x \right] + C\]
\[ = - \frac{1}{2}\cot x + C\]

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Chapter 19: Indefinite Integrals - Exercise 19.02 [Page 15]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.02 | Q 34 | Page 15

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