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sec^2 10° – cot^2 80° = ?

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Question

sec2 10° – cot2 80° = ?

Options

  • 0

  • 1

  • `3/4`

  • `1/2`

MCQ
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Solution

1

Explanation:

Given expression = sec2 10° – cot2(90° – 10°)

= sec2 10° – tan2 10°   ...[∵ sec2θ – tan2θ = 1]

= 1

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Chapter 12: Trigonometric Ratios of Some Complemantary Angles - MULTIPLE-CHOICE QUESTIONS (MCQ) [Page 593]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 12 Trigonometric Ratios of Some Complemantary Angles
MULTIPLE-CHOICE QUESTIONS (MCQ) | Q 9. | Page 593
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