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Question
sec2 10° – cot2 80° = ?
Options
0
1
`3/4`
`1/2`
MCQ
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Solution
1
Explanation:
Given expression = sec2 10° – cot2(90° – 10°)
= sec2 10° – tan2 10° ...[∵ sec2θ – tan2θ = 1]
= 1
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