Question

`(2 sin^2 63^circ + 1 + 2 sin^2 27^circ)/(3 cos^2 17^circ - 2 + 3 cos^2 73^circ)` = ?

Options

• `2/3`

• `3/2`

• 2

• 3

Answer 1

3

Explanation:

Given expression = `(2 sin^2 63^circ + 2 sin^2 (90^circ - 30^circ) + 1)/(3 cos^2 17^circ + 3 cos^2 (90^circ - 17^circ) - 2)`

= `(2 sin^2 63^circ + 2 cos^2 63^circ + 1)/(3 cos^2 17^circ + 3 sin^2 17^circ - 2)`

= `(2(sin^2 63^circ + cos^2 63^circ) + 1)/(3(cos^2 17^circ + sin^2 17^circ) - 2)`

= `((2 xx 1) + 1)/((3 xx 1) - 2)`

= `(2 + 1)/(3 - 2)`

= 3