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Question
Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards:
| Whose card | Length | Width | Perimeter | Area |
| Sanya | 10 cm | 8 cm | ||
| Manav | 11 cm | 44 cm | ||
| Aarushi | 8 cm | 80 square cm | ||
| Kabir | 40 cm | 100 square cm |
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Solution
Perimeter of Sanya’s card = Sum of all its sides
= 10 + 8 + 10 + 8
= 36 cm
Length of Manav’s card = 11 cm Perimeter of his card = 44 cm
We have to find the width of Manav’s card.
Perimeter of card = Sum of all its sides
= 11 + 11 + sum of 2 other sides
= 22 + sum of 2 other sides
Now, a sum of two other sides
= 44 − 22
= 22 cm
The two other sides of the greeting cards are width. So, the width of Manav’s card
= 22 ÷ 2
= 11 cm
Width of Aarushi’s card = 8 cm Area of the card = 80 square cm
Now, we have to find the length of the card.
Area of card
= Length of card × 8 cm
= 80 square cm
So, on dividing the area of a card by its width, we can get its length.
Therefore, length of Aarushi’s card = 80 ÷ 8
= 10 cm
| Whose card | Length | Width | Perimeter | Area |
| Sanya | 10 cm | 8 cm | 36 cm | 80 square cm |
| Manav | 11 cm | 11 cm | 44 cm | 121 square cm |
| Aarushi | 10 cm | 8 cm | 36 cm | 80 square cm |
| Kabir | 10 cm | 10 cm | 40 cm | 100 square cm |
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