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Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards: Whose card Length Width Perimeter Area Sanya 10 cm 8 cm Manav 11 cm 44 cm Aarus - Mathematics

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Question

Sanya, Aarushi, Manav and Kabir made greeting cards. Complete the table for their cards:

Whose card Length Width Perimeter Area
Sanya 10 cm 8 cm    
Manav 11 cm   44 cm  
Aarushi   8 cm   80 square cm
Kabir     40 cm 100 square cm
Chart
Sum
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Solution

Perimeter of Sanya’s card = Sum of all its sides

= 10 + 8 + 10 + 8

= 36 cm

Length of Manav’s card = 11 cm Perimeter of his card = 44 cm

We have to find the width of Manav’s card.

Perimeter of card = Sum of all its sides

= 11 + 11 + sum of 2 other sides

= 22 + sum of 2 other sides

Now, a sum of two other sides

= 44 − 22

= 22 cm

The two other sides of the greeting cards are width. So, the width of Manav’s card

= 22 ÷ 2

= 11 cm

Width of Aarushi’s card = 8 cm Area of the card = 80 square cm

Now, we have to find the length of the card.

Area of card

= Length of card × 8 cm

= 80 square cm

So, on dividing the area of a card by its width, we can get its length.

Therefore, length of Aarushi’s card = 80 ÷ 8

= 10 cm

Whose card Length Width Perimeter Area
Sanya 10 cm 8 cm 36 cm 80 square cm
Manav 11 cm 11 cm 44 cm 121 square cm
Aarushi 10 cm 8 cm 36 cm 80 square cm
Kabir 10 cm 10 cm 40 cm 100 square cm
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Chapter 11: Area and its Boundary - Area and its Boundary [Page 149]

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NCERT Math - Magic [English] Class 5
Chapter 11 Area and its Boundary
Area and its Boundary | Q f) | Page 149

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