Advertisements
Advertisements
Question
Revenue function ‘R’ and cost function ‘C’ are R = 14x – x2 and C = x(x2 – 2). Find the
- average cost
- marginal cost
- average revenue and
- marginal revenue.
Advertisements
Solution
R = 14x – x2 and C = x(x2 – 2)
C = x3 – 2x
(i) Average Cost (AC) = `"Total cost"/"Output" = ("C"(x))/x`
`= (x^3 - 2x)/x`
`= x^3/x - (2x)/x`
= x2 – 2
(ii) Marginal Cost (MC) = `"dC"/"dx"`
`= "d"/"dx" (x^3 - 2x)`
`= "d"/"dx" (x^3) - 2 "d"/"dx" (x)`
= 3x2 – 2
(iii) Average Revenue R = 14x – x2
Average Revenue (AR) =`"Total Revenue"/"Output" = ("R"(x))/x`
`= (14x - x^2)/x`
`= (14x)/x - x^2/x`
= 14 - x
(iv) Marginal Revenue (MR) = `"dR"/"dx"`
`= "d"/"dx" (14x - x^2)`
`= 14 "d"/"dx" (x) - "d"/"dx" (x^2)`
= 14(1) – 2x
= 14 – 2x
APPEARS IN
RELATED QUESTIONS
If the demand law is given by p = `10e^(- x/2)` then find the elasticity of demand.
The supply function of certain goods is given by x = a`sqrt("p" - "b")` where p is unit price, a and b are constants with p > b. Find elasticity of supply at p = 2b.
Show that MR = p`[1 - 1/eta_"d"]` for the demand function p = 400 – 2x – 3x2 where p is unit price and x is quantity demand.
For the demand function x = `25/"p"^4`, 1 ≤ p ≤ 5, determine the elasticity of demand.
Find the price elasticity of demand for the demand function x = 10 – p where x is the demand p is the price. Examine whether the demand is elastic, inelastic, or unit elastic at p = 6.
For the demand function p x = 100 - 6x2, find the marginal revenue and also show that MR = p`[1 - 1/eta_"d"]`
Average fixed cost of the cost function C(x) = 2x3 + 5x2 – 14x + 21 is:
Instantaneous rate of change of y = 2x2 + 5x with respect to x at x = 2 is:
Profit P(x) is maximum when
The demand function is always
