Advertisements
Advertisements
Question
Find the values of x, when the marginal function of y = x3 + 10x2 – 48x + 8 is twice the x.
Advertisements
Solution
y = x3 + 10x2 – 48x + 8
Marginal function, `"dy"/"dx"` = 3x2 + 10(2x) – 48
= 3x2 + 20x – 48
Given that, the marginal function is twice the x.
Therefore, 3x2 + 20x – 48 = 2x
3x2 + 18x – 48 = 0
Divide throughout by 3, x2 + 6x – 16 = 0
(x + 8) (x – 2) = 0
x = -8 (or) x = 2
The values of x are -8, 2.
APPEARS IN
RELATED QUESTIONS
Find the elasticity of demand in terms of x for the following demand laws and also find the value of x where elasticity is equal to unity.
p = a – bx2
Find the price elasticity of demand for the demand function x = 10 – p where x is the demand p is the price. Examine whether the demand is elastic, inelastic, or unit elastic at p = 6.
The total cost function for the production of x units of an item is given by C = 10 - 4x3 + 3x4 find the
- average cost function
- marginal cost function
- marginal average cost function.
Find out the indicated elasticity for the following function:
p = `10 e^(- x/3)`, x > 0; ηs
Find the elasticity of supply when the supply function is given by x = 2p2 + 5 at p = 1.
Marginal revenue of the demand function p = 20 – 3x is:
The elasticity of demand for the demand function x = `1/"p"` is:
For the cost function C = `1/25 e^(5x)`, the marginal cost is:
If the average revenue of a certain firm is ₹ 50 and its elasticity of demand is 2, then their marginal revenue is:
Average cost is minimum when:
