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Reduce the following equation into intercept form and find their intercepts on the axes. 4x – 3y = 6 - Mathematics

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Question

Reduce the following equation into intercept form and find their intercepts on the axes.

4x – 3y = 6

Sum
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Solution

The given equation is 4x – 3y = 6.

It can be written as

`(4"x")/6 - (3"y")/6 = 1`

`(2"x")/3 - "y"/2 = 1`

i.e., `"x"/((3/2)) + "y"/(-2) = 1` ...........(1)

This equation is of the form `"x"/"a" + "y"/"b" = 1`, where a = `3/2` and b = −2.

Therefore, equation (1) is in the intercept form, where the intercepts on the x and y axes are `3/2` and −2 respectively.

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Chapter 10: Straight Lines - Exercise 10.3 [Page 227]

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NCERT Mathematics [English] Class 11
Chapter 10 Straight Lines
Exercise 10.3 | Q 2.2 | Page 227
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