Question

Reduce the following equation into intercept form and find their intercepts on the axes.

3y + 2 = 0

Answer 1

The given equation is 3y + 2 = 0.

It can be written as

3y = −2

i.e., `"y"/((- 2/3)) = 1` ...........(1)

This equation is of the form `"x"/"a" + "y"/"b" = 1`, where a = 0 and b = `−2/3`.

Therefore, equation (1) is in the intercept form, where the intercepts on the y-axis is `-2/3` and it has no intercept on the x-axis.